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2u^2+21u-69=0
a = 2; b = 21; c = -69;
Δ = b2-4ac
Δ = 212-4·2·(-69)
Δ = 993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{993}}{2*2}=\frac{-21-\sqrt{993}}{4} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{993}}{2*2}=\frac{-21+\sqrt{993}}{4} $
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